tok, unexpected result (tok array item has incorrect len)

[r0n]

Macro treadmill_log_SetImageLog

Code:

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str s="e:\__qm_testdirs\_treadmill_log_test\log\‎10-‎6-‎2016.JPG"
str fn.getfilename(s) ;; 10-‎6-‎2016
ARRAY(str) arr
tok fn arr -1 "-" ;; [0]=10 , [1]=6 , [2]=2016
out arr[0]
out arr[1]
out arr[2]
out arr[0].len ;; OUTPUT: 5 , in stead of 2

The .len of the first item in arr should be '2', but I get '5'
"s" is an actual file and the filename is the date when the picture was taken.
The first item = "10" which is 2 characters in length (len), but why am I getting '5' as an output?

I have tried the same code in a different macro but in stead of the full path I put in "s", i put the only the date in it "10-6-2016" and then it works! (I get '2' in the output pane below)

[Gintaras]

Your string contains some hidden characters. Probably copied from some app that adds them.

example
Macro Macro2818

Code:

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out
str s

;normal
s="a"
out s.len
outb s s.len

;replaced from your string; the hidden characters remains
s="‎a"
out s.len
outb s s.len

;result
;1
;61
;4
;E2 80 8E 61

google for E2 80 8E

[r0n]

That explains why it worked in another macro!
Thank you!

[r0n]

I found out where it went wrong I think.

I have some images taken with the Iphone 4 which I then copy to the pc.
I then run a script based on this example:
MS Word document built-in Properties (get file extended properties)

I assume the example script is ok, but the problem is the way the "Date taken" get's written by the phone.
I tested it again and it this seems to be the case.

This still leaves me with the hidden characters and this leads me to this question:
Is it possible to remove the hidden characters from a string, especially the "E2 80 8E"?

[Gintaras]

s.findreplace("copy paste what seems to be empty but actually contains these 3 bytes")

Macro hidden characters

Code:

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out
str s

;normal
s="a"
out s.len
outb s s.len

;replaced from your string; the hidden characters remains
s="‎a"
out s.len
outb s s.len

;result
;1
;61
;4
;E2 80 8E 61

;s.findreplace("‎") ;;3 hidden bytes in ""
s.findreplace("[0xE2][0x80][0x8E]") ;;visual
out s
out s.len
outb s s.len

[r0n]

Thank you!!!